Mathematics · Challenge

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Volume scalingRunning
Volume block. Cistern height at 2.56 dm. Volume required 1080 L, Base × height 184.32 L. Currently volume required is over by 895.68 L.TUNINGh2.56 DM1080 L
t = 0.0s

Volume required

1080L

Base × height

184.32L

2.56 dm

Volume block. Cistern height at 2.56 dm. Volume required 1080 L, Base × height 184.32 L. Currently volume required is over by 895.68 L.

What has to balanceV=AbasehV = A_{base} h

What is happening

You take control of a rainwater cistern being sized for a rooftop garden.

The cistern comes up short. It must hold 1080 L, its base area is fixed at 72 dm², and the planned height is wrong.