Chemistry · Explorer

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Solution concentrationRunning
Solution beaker. Final volume at 4.46 L. Moles present 0.6 mol, Concentration × volume 1.12 mol. Currently moles present is short by 0.515 mol.TUNINGCONCENTRATION × VOLUMEMOLES PRESENT4.46 L · 0.6 mol
t = 0.0s

Moles present

0.6mol

Concentration × volume

1.12mol

4.46 L

Solution beaker. Final volume at 4.46 L. Moles present 0.6 mol, Concentration × volume 1.12 mol. Currently moles present is short by 0.515 mol.

What has to balanceC=nVC = \frac{n}{V}

What is happening

You are called to a pharmacy diluting a stock solution for a paediatric dose.

The dose as made up would be unsafe. 0.6 mol of active compound must end up at 0.25 mol/L, and the final volume is set wrong.